A particle starts from rest. Its acceleration (a) versus time (t) is as shown in the figure. The maximum speed of the particle will be:660 m/s55m/s110m/s550 m/s

Click here:point_up_2:to get an answer to your question :writing_hand:a particle starts from rest its acceleration a versus time t is as shown in 2
Click here👆to get an answer to your question ✍️ A particle starts from rest- Its acceleration -a- versus time -t- is as shown in the figure- The maximum speed of the particle will be-660 m-s55m-s110m-s550 m-s
Given-u-0m-s Particle initially at restAcceleration- a-dvdtdv-adtv-x222B-adt- - - - - - - - -1-From the above equation- velocity of the particle is equal to the area under the acceleration-time curve-From the given acceleration-time graph-vmax-12-xD7-base-xD7-heightvmax-12-xD7-11-xD7-10vmax-55m-sThe correct option is B

A particle starting from rest. Its acceleration (a) versus time (t

⏩SOLVED:A particle starts from rest and accelerates as shown in

AT (B) P CDTI 49. A particle starts from rest. Its acceleration (a

Solved A particle starts from rest and accelerates as shown

A particle starts from rest. Its acceleration at time t=0 is 5 m//s^(2

A particle starts from rest. Its acceleration time graph is as

A particle starts from rest. Its acceleration time graph is as

A particle starts from rest. Its acceleration (a) versus time (t

The particle starts from rest. Its accelerationa versus timet is

SOLVED: A particle starts from rest and accelerates as shown in

Solved A particle starts from rest and accelerates as shown

A particle starts from rest. Its acceleration (a) versus time